Ammonia produced when 0.75 g of a substance was kjeldahlised neutralised 30 cm^(3) of 0.25 NH_(2)SO_(4). Calculate the persentage of nitrogen in the compound.

Ammonia produced when 0.75 g of a substance was kjeldahlised neutralis

1.	Ammonia produced when 0.75 g of a substance was kjeldahlised neutralised 30 cm^(3) of 0.25 NH_(2)SO_(4). Calculate the persentage of nitrogen in the compound.
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the organic <a href="https://interviewquestions.tuteehub.com/tag/substance-1231528" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTANCE">SUBSTANCE</a> =0.75 g <br/> Volume of `H_(2)SO_(4)` <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> up `=30 cm^(3)` <br/> Normality of sulphuric acid `= 0.25 N` <br/> `30 cm^(3)` of `H_(2)SO_(4)` of normality `0.25 N equiv 30 cm^(3)` of `NH_(3)` solution of normality 0.25 N <br/> But `1000 cm^(3)` of ammonia solution of normality 1 contain 14 g of nitrogen. <br/> `:.` Therefore, `30 cm^(3)` of 0.25 N ammonia solution will contain nitrogen `=14/1000xx30xx0.25` <br/> `:.` Percentage of nitrogen `=("Mass of nitrogen")/("Mass of substance")xx100=14/1000xx(30xx0.25)/(0.75)xx100=14.00`.</body></html>