Ammonium carbamate decompses as NH_(2) COONH_(4) (s) hArr 2 NH_(3) (g) + CO_(2) (g) . In a closed vessel containing ammonium carbamate in equilibrium , NH_(3) is added such that the partial pressure of NH_(3) now equals original total pressure. Calculate the ratio of total pressure not to the original pressure.

Ammonium carbamate decompses as NH_(2) COONH_(4) (s) hArr 2 NH_(3) (g)

1.	Ammonium carbamate decompses as NH_(2) COONH_(4) (s) hArr 2 NH_(3) (g) + CO_(2) (g) . In a closed vessel containing ammonium carbamate in equilibrium , NH_(3) is added such that the partial pressure of NH_(3) now equals original total pressure. Calculate the ratio of total pressure not to the original pressure.
Answer» <html><body><p></p>Solution :the <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of 2 :1 Thus, ` p_( NH_(3)) = 2/3 P, p_(CO_(2))= 1/3 P :. K_(P) = (p_(NH_(3)))^(2) (p_(CO_(2)))^(2) = (2/3P)^(2) (1/3 P) = 4/27 P^(3)`<br/> After <a href="https://interviewquestions.tuteehub.com/tag/adding-2399902" style="font-weight:bold;" target="_blank" title="Click to know more about ADDING">ADDING</a> ` NH_(3) , p_(NH_(3))= P("<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> "):. P^(2) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> p_(CO_(2))= K_(p) = 4/27 P^(3) or p_(CO_(2)) = 4/ 27 P` <br/>`:. " Total pressure now " = p_(NH_(3))+ p_(CO_(2))= P + 4/27 P = 31/27 P`<br/>`:." Ratioof totalpressure now to the original pressure "= 31 /27 .`</body></html>