Saved Bookmarks
| 1. |
Ammonium carbamate decompses as NH_(2) COONH_(4) (s) hArr 2 NH_(3) (g) + CO_(2) (g) . In a closed vessel containing ammonium carbamate in equilibrium , NH_(3) is added such that the partial pressure of NH_(3) now equals original total pressure. Calculate the ratio of total pressure not to the original pressure. |
|
Answer» Solution :the RATIO of 2 :1 Thus, ` p_( NH_(3)) = 2/3 P, p_(CO_(2))= 1/3 P :. K_(P) = (p_(NH_(3)))^(2) (p_(CO_(2)))^(2) = (2/3P)^(2) (1/3 P) = 4/27 P^(3)` After ADDING ` NH_(3) , p_(NH_(3))= P("GIVEN "):. P^(2) XX p_(CO_(2))= K_(p) = 4/27 P^(3) or p_(CO_(2)) = 4/ 27 P` `:. " Total pressure now " = p_(NH_(3))+ p_(CO_(2))= P + 4/27 P = 31/27 P` `:." Ratioof totalpressure now to the original pressure "= 31 /27 .` |
|