Ammonium carbamate (NH_2COONH_4)decomposes as: NH_2COONH_4(s) hArr 2NH_3(g) + CO_2(g) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH_3 becomes equal to original total pressure. Calculate the ratio of final total pressure to the original pressure.

Ammonium carbamate (NH_2COONH_4)decomposes as: NH_2COONH_4(s) hArr 2N

1.	Ammonium carbamate (NH_2COONH_4)decomposes as: NH_2COONH_4(s) hArr 2NH_3(g) + CO_2(g) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH_3 becomes equal to original total pressure. Calculate the ratio of final total pressure to the original pressure.
Answer» Solution :SUPPOSE the total pressure of the mixture initially is p. This is DUE to the PARTIAL pressure of `NH_3` and `CO_2` which are present in the ratio of 2:1. `p(NH_3)=2/3p` and `p(CO_2)=1/3p` `THEREFORE K_p=p(NH_3)^2 xx p(CO_2)=(2/3p)^2XX(1/3p)=4/27p^3` After adding`NH_3 , p(NH_3)=p` (given) `therefore p^2xxp(CO_2)=K_p=4/27p^3` `therefore p(CO_2)=4/27p` Final total pressure =`p(NH_3)+p(CO_2)=p+4/27p =31/27p` `therefore` Ratio of final total pressure to the original pressure =31:27