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Among H_(2),He_(2)^(+) ,Li_(2),Be_(2)_,C_(2),N_(2),O_(2)^(-) and F_(2) , the number of diamagnetic species is (Atomic numbers : H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9) |
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Answer» `H_(2)(2) = sigma (1s)^(2)` (Diamagnetic) `He_(2)^(+) = sigma (1s)^(2), sigma^(**)(1s)^(1)` (Paramagnetic) `LI (2) (6) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2S)^(2) ` (Diamgnetic) ` Be_(2) (8) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2)` (Diamagnetic) ` Be_(2) (10) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), ` `pi(2p_(x))^(1) = pi(2p_(y))^(1)`(Paramagnetic) ` C_(2) (12) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), ` `pi(2p_(x))^(2) = pi(2p_(y))^(2)`(Diamagnetic) ` N_(2) (14) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), ` `pi(2p_(x))^(2) = pi(2p_(y))^(2),sigma(2p_(z))^(2)`(Diamagnetic) ` O_(2)^(-) (17) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), ` `sigma(2p_(z))^(2) = pi(2p_(y))^(2),sigma(2p_(z))^(2)` ` pi^(**) (2p_(x))^(2) = pi^(**) (2p_(y))^(1) ` (paramagnetic) ` F_(2) (18) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), ` `sigma(2p_(z))^(2) = pi(2p_(x))^(2),sigma(2p_(y))^(2)` `pi^(**) (2p_(x))^(2) = pi^(**) (2p_(y))^(2)`(Diamagnetic) THEREFORE , the TOTAL NUMBER of diamagnetic species is six . |
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