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Among KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+), unpaired electron is present in

Answer» <html><body><p>`NO_(2)^(+) and BaO_(2)` <br/>`KO_(2) and AlO_(2)^(-)` <br/>`KO_(2)` only <br/>`BaO_(2)`only </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> present :<br/>`NO_(2)^(+) = <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> + 16 - 1 = 22 , BaO_(2) = 56 + 16 = 72 `<br/> `AlO_(2)^(-) = 13 + 16 + 1 = 30 `<br/> and `KO_(2) = 19 + 16 = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>`<br/> Thus , <a href="https://interviewquestions.tuteehub.com/tag/olny-3760673" style="font-weight:bold;" target="_blank" title="Click to know more about OLNY">OLNY</a> `KO_(2)` is odd electron species.</body></html>


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