InterviewSolution
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InterviewSolution
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Among the complexs, `[N_(CO)_(4)],[NI(CN)_(4)]^(2-)` anhd `[NiCI_(4)]^(2-)`A. `[Ni(CO)_(4)]` si diamagnetic but `[Ni(CO)_(4)]` and `[NI(CN)_(4)]^(2-)` are paramagenticB. `[Ni(CN)_(4)]^(2-)` and `[NI(CO)_(4)` aren diamagnetic but `[NiCI_(4))^(2-) is paramagneticC. `[Ni(CI_(4)]^(2-)` and `[Ni(CO)_(4)]` are diamgnetic but `[Ni(CN)_(4)]^(2-)` is paramagneticD. `[Ni(C)_(4)]^(2-)` and `[Ci(CO)_(4)]^(-2)` are diamagnetic but `[Ni(CO)_(4)]` is paramagnetic |
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Answer» (b) The oxidation state of Ni in `[Ni(CN_(4)]^(2+)` and `[NiCI_(4)]^(2-)` is +2 while in `[Ni(CO)_(4)]` it is in zero oxidation state. Since CO and `CI^(-)` are strong ligands "thereofe" they cause paring of the unpaired electrons. `:Therefore" `[Ni(CO)_(4)] and [Ni(CN)_(4)]^(2-)` are diagnetic Whereas, `CI^(-)` is a weak ligand that does not cause pairing of electons , resulting in paramagnetic complex. Hence, `[NiCI_(4)]^(2-)` is paramagnetic. |
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