1.

An adult weighting 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jog for 6 km, calculate the energy utillised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the form of food. calculate the energy equivalents of food that would required to compensate energy utilised for jogging.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :W = mg = 600 N <br/> h = 0.25 m <br/>l = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> m <br/> d = 6 km = 6000 m <br/> ` :. ` Total number of <a href="https://interviewquestions.tuteehub.com/tag/steps-1227441" style="font-weight:bold;" target="_blank" title="Click to know more about STEPS">STEPS</a>= `(6000)/1 = 6000` <br/> Total energyutilisedin jogging <br/> ` = n xx mgh`<br/> ` = n xx mgh ` <br/> ` = 6000 xx 600 xx0.25 `<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> <br/> `= 9 xx10^(5)J` <br/> Since, 10 % intake <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is utilised in jogging<br/> ` :. `Total intake energy ` = 10 xx 9 xx 10^(5)J`<br/> ` = 9xx10^(6)J`</body></html>


Discussion

No Comment Found

Related InterviewSolutions