An alkyl halide of formula `C_(4)H_(9)Cl` on treatement with alcoholic potash gives alkenes `C_(4)H_(8)`. Both alkenes on tratment with HI gives 2-iodo butate. Isomeric alkenes areA. `CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CHCH_(3)`B. `CH_(3)CH_(2)=CH_(2) and (CH_(3))_(2)C=CH_(2)`C. `CH_(3)CH=CH_(2) and CH_(3) CH=CHCH_(3)`D. `CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CH_(2)`

An alkyl halide of formula `C_(4)H_(9)Cl` on treatement with alcoholic

1.	An alkyl halide of formula `C_(4)H_(9)Cl` on treatement with alcoholic potash gives alkenes `C_(4)H_(8)`. Both alkenes on tratment with HI gives 2-iodo butate. Isomeric alkenes areA. `CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CHCH_(3)`B. `CH_(3)CH_(2)=CH_(2) and (CH_(3))_(2)C=CH_(2)`C. `CH_(3)CH=CH_(2) and CH_(3) CH=CHCH_(3)`D. `CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CH_(2)`
Answer» Correct Answer - A Because rate of reaction depends upon concentration of anly `3^(@)` alkyl halide not on concentration of aq. Potash. (a) Molecular formula `C_(4)H_(9)Cl` has four isomers, thses are n-butyl chloride,sec. butyl chloride. Former two on elimination gives 1-butene and 2-butene respectively and latter two on elimination gives siobutylene. 1-butene and 2-butene are treated withHI gives 2-iodobutane. 1-butene and 2-butene are position isomers. Isobutylene is treated with HI gives t-butyl iodide hence answer is (a)

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