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An alloy of copper and zinc weight 320 g in water and 302 g in a liquid of density 1.4 g cm^(-3). If the density of copper is 8.9 g cm^(-3) and that of the zinc is 7.4 g cm^(-3), find the measure of the masses of copper and zinc in the alloy. |
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Answer» SOLUTION :(i) Give the mass of alloy in water and liquid as `W_(2)` and `W_(3)`. Let the mass of the alloy in air be `W_(1)`. ACCORDING to Archimedes' principle, The density of water `=(W_(1))/(W_(1)-W_(2))` The density of liquid `=(W_(1)xxW_(3))/(W_(1)-W_(2))` From the above equations, find the weight of the alloy in air. Find the volume of the alloy from the weight of the displaced water. Then, the TOTAL volume of copper and zinc is the volume of copper be expressed by `("mass of copper")/("density of copper")` Similary, volume of zinc can be REPLACED by `("mass of zinc")/("density of copper")` `implies (M_(cu))/(8.9)=(M_(zn))/(7.4)` Volume of the alloy. Now, replace `M_(zn)` with (mass of Alloy in air `-M_(cu))` From the above EQUATION, find the masses of copper and zinc present in the alloy. (ii) Maximum density `=5 g cm^(-3)` |
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