An alpha-particle and a proton are accelerated from rest by the same potential, thenthe ratio of their de-Broglie wavelength is

An alpha-particle and a proton are accelerated from rest by the same p

1.	An alpha-particle and a proton are accelerated from rest by the same potential, thenthe ratio of their de-Broglie wavelength is
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>`<br/>`1/sqrt2`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2sqrt2-1838926" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT2">2SQRT2</a>`<br/>`2`</p>Solution :`lambda = h/(sqrt(2qVm)) , lambda_(alpha) = h/(sqrt(2xx2xxV <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> m_(alpha)))` <br/>`implieslambda_(alpha) = (h)/(sqrt(2xx2xx V xx <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` <br/>`lambda _P =(h)/(sqrt(2xx1xxVxx m_p)) , lambda_p = (h)/(sqrt(2xx1xxV xx 1))` <br/>`(lambda_p)/(lambda_(alpha)) = sqrt((16)/(2)) implies(lambda_P)/(lambda_(alpha)) = 2sqrt2`</body></html>