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An `(alpha)`-particle and a proton are both simultaneously projected in opposite direction into a region of constant magnetic field perpendicular to the direction of the field. After some time it is found that the velocity of the `(alpha)`-particle has changed in a direction by `45^(@)`. Then at this time, the angle between velocity vectors of `(alpha)`-particle and proton isA. `90^(@)`B. `45^(@)`C. `45^(@)+90^(@)`D. `(45^(@)+90^(@))/2` |
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Answer» Correct Answer - c `omega_(alpha) ((2e)B)/(4m) =1/2 (eB)/m` `omega_(p)=(eB)/m` `theta_(alpha)=45^(@)` `theta_(p)=90^(@)` from their original directions. |
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