InterviewSolution
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InterviewSolution
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An aqueous pink solution of cobalt (II) chloride changes to deep blue on addition of excess of `HCl`. This is because ....... .A. `[Co(H_(2)O_(6)]^(2+)` is transformed into `[CoCl_(6)]^(4-)`B. `[Co(H_(2)O)_(6)]^(2+)` is transformed into `[CoCl_(4)]^(2-)`C. tetrahedral complexes have smaller crystal field splitting than octahedral complexesD. Tetrahedral complexes have larger crystal field splitting than octahedral complex |
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Answer» Correct Answer - B::C Aqueous pink solution of cobalt (II) chloride is due to electronic transition of electron from `t_(2g)` to `e_(g)` energy level of `[Co(H_(2)O)_(6)]^(2+)` complex. When excess of HCl is added to this solution (i) `[Co(H_(2)O)_(6)]^(2+)` is transformed into `[CoCl_(4)]^(2-)`. (ii) Tetrahedral complexes have smaler crystal field splitting than octahedral complexes because `Delta_(t)=4/9 Delta_(0)` Hence , option (b) and (c) are correct choices. |
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