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An electric current is passed through an aqueous solution of lead(II) chloride. The half-reactions are: Cathode- Pbx+(aq) + xe−→Pb(s) Anode - Cl−y(aq)→Cl(s)+ye− Find the value of x + y.3

Answer» An electric current is passed through an aqueous solution of lead(II) chloride. The half-reactions are:
Cathode- Pbx+(aq) + xePb(s)
Anode - Cly(aq)Cl(s)+ye
Find the value of x + y.
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