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An electrolytic cell contains a solution of `Ag_(2)SO_(4)` and have platinum electrodes. A current is passed until 1.6gm of `O_(2)` has been liberated at anode. The amount of silver deposited at cathode would beA. 108 gB. 1.6 gC. 0.8 gD. 21.60 g |
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Answer» Correct Answer - D Number of equivalents of oxygen `= (1.6)/(8) = 0.2` `:.` Number of equivalents of Ag deposited `= 0.2` Mass of Ag deposited `= 0.2 xx 108 = 21.6 g` |
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