An element `A` in a compound `ABD` has oxidation number `A^(n-)`. It is oxidised by `Cr_(2)O_(7)^(2-)` in acid medium. In the experiment `1.68xx10^(-3)` moles of `K_(2)Cr_(2)O_(7)` were used for `3.26xx10^(-3)` moles of `ABD`. The new oxidation number of `A` after oxidation is:A. `3`B. `3-n`C. `n-3`D. `+n`

An element `A` in a compound `ABD` has oxidation number `A^(n-)`. It i

1.	An element `A` in a compound `ABD` has oxidation number `A^(n-)`. It is oxidised by `Cr_(2)O_(7)^(2-)` in acid medium. In the experiment `1.68xx10^(-3)` moles of `K_(2)Cr_(2)O_(7)` were used for `3.26xx10^(-3)` moles of `ABD`. The new oxidation number of `A` after oxidation is:A. `3`B. `3-n`C. `n-3`D. `+n`
Answer» Correct Answer - B Meq. Of `K_(2)Cr_(2)O_(7)`= Meq. Of `ABD` `n-` factor of `K_(2)Cr_(2)O_(7)` in acidic medium `=6` `6xx1.68xx10^(-3)=x xx3.26xx10^(-3)` `x=3` `implies` New oxidation state of `A^(-n)` will be `= -n+3`

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