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An equation is given as `(p +(a)/(V^(2))) = b(theta)/(V)`,where `p=` pressure `V=` volumen and `theta =` absolute temperature. If a and b are constants, then dimensions of a will beA. `[ML^(5)T^(-2)]`B. `[M^(-1)L^(5)T^(-2)]`C. `[ML^(-5)T^(-1)]`D. `[ML^(5)T]` |
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Answer» Correct Answer - A From principle of homogeneity of dimensions. Dimensions of `p =` dimensions of `(a)/(V^(2))` `p = (a)/(V^(2)) rArr a = pV^(2)` `=[ML^(-1)T^(-2)] [L^(3)]^(2) = [ML^(5)T^(-2)]` |
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