An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?

An equi – convex lens of glass, refractive index 1.5 has focal lengt

1.	An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?
Answer» <html><body><p><strong>Answer:</strong></p><p>Correct option is</p><p>B</p><p>8</p><p>15</p><p> </p><p> </p><p>Given, </p><p>μ </p><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></p><p> </p><p> =1.5</p><p><a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> </p><p>1</p><p> </p><p> =0.2m</p><p>f </p><p>2</p><p> </p><p> =(−0.5)</p><p>μ </p><p>2</p><p> </p><p> =?</p><p></p><p>Using <a href="https://interviewquestions.tuteehub.com/tag/lens-1071845" style="font-weight:bold;" target="_blank" title="Click to know more about LENS">LENS</a> <a href="https://interviewquestions.tuteehub.com/tag/makers-1085075" style="font-weight:bold;" target="_blank" title="Click to know more about MAKERS">MAKERS</a> formula and taking <a href="https://interviewquestions.tuteehub.com/tag/ratios-1177874" style="font-weight:bold;" target="_blank" title="Click to know more about RATIOS">RATIOS</a>, </p><p>f </p><p>2</p><p> </p><p> </p><p>f </p><p>1</p><p> </p><p> </p><p> </p><p> = </p><p>(μ </p><p>1</p><p> </p><p> −1)</p><p>(μ </p><p>2</p><p> </p><p> −1)</p><p> </p><p> </p><p></p><p>⇒ </p><p>(−0.5)</p><p>0.2</p><p> </p><p> = </p><p>(1.5−1)</p><p>( </p><p>μ </p><p>e</p><p> </p><p> </p><p>1.5</p><p> </p><p> −1)</p><p> </p><p> </p><p></p><p>⇒ </p><p>0.5</p><p>0.2×0.5</p><p> </p><p> =(1− </p><p>μ </p><p>e</p><p> </p><p> </p><p>1.5</p><p> </p><p> )</p><p></p><p>⇒ </p><p>μ </p><p>e</p><p> </p><p> </p><p>1.5</p><p> </p><p> =0.8</p><p></p><p>⇒μ </p><p>e</p><p> </p><p> = </p><p>8</p><p>15</p><p> </p><p> </p></body></html>

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An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?​

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An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?