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An equiconvex lens of refractive index `n_(2)` is placed such that the refractive index of the surrouding media is as shown. The lens : A. must be diverging if `n_(2)` is less than the aritmetic mean of `n_(1)` and `n_(3)`B. must be converging if `n_(2)` is greater than the arithmetic mean of `n_(1)` and `n_(3)`C. may be diverging if `n_(2)` is less than the arihmetic mean of `n_(1)` and `n_(3)`D. will neither be diverging nor converging if `n_(2)` is equal to arithmetic mean of `n_(1)` and `n_(3)` |
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Answer» Correct Answer - a,b,d `f=(n_(1)R)/(2n_(2)-n_(1)-n_(3))` or `(n_(3)R)/(2n_(2)-n_(1)-n_(3))` if `n_(2)lt(n_(1)+n_(3))/(2)rArrf is -ve rArr` lens is diverging if `n_(2)gt(n_(1)+n_(3))/(2) rArrf is+ve rArr` lens is converging. If `n_(2)=n_(1)+n_(2) rArr f=infty` neither converging nor diverging. |
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