InterviewSolution
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InterviewSolution
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An ethereal solution of an alkyl halide preferably the bromide of iodide, is treated with sodium `2R-X+2Na overset("Ether")toR-R+2NaX` `2CH_(3)-Br+2Na overset("Ether")toCH_(3)-CH_(3)+2NaBr` `CH_(3)CH_(2)Br+2Na+CH_(3)Br overset("Ether")toCH_(3)CH_(2)-CH_(3)+2NaBr` In this reaction, the product has new (C-C) bond with the same type of alkyl halide, the product has symmetery and this helps in deciding the nature of reacting halide. Intermediates are free radicals `CH_(3)CH_(2)CH_(2)CH_(3) underset("hv controlled")overset(Cl_(2))to overset("Na//ether")to` Major product of the above reaction isA. `CH_(3)(CH_(2))_(6)CH_(3)`B. `CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)CH_(2)CH_(3)`C. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)CH_(2)underset(CH_(3))underset(|)(CH)CH_(3)`D. None of these |
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Answer» Correct Answer - B Intermediate is `CH_(3)CH_(2)CH_(2)CH_(3)` |
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