An ice cube of mass 1 kg at 0 ° C is kept in a deffered container at 227 ° C. The specific heat-proportional relationship of the vessel varies with the temperature of s = A + BT, where A = 100 calories kg^-1 kelvin^-1 and. B = 2 X 10^-2 calory kg^-1. If the final temperature of the vessel is 27 ° C, what will be the mass of the vessel? (latent heat of fusion of water = 8x10^4 calories kg^-1, specific heat of water = 10^3 calories kg^-1.)

An ice cube of mass 1 kg at 0 ° C is kept in a deffered container at

1.	An ice cube of mass 1 kg at 0 ° C is kept in a deffered container at 227 ° C. The specific heat-proportional relationship of the vessel varies with the temperature of s = A + BT, where A = 100 calories kg^-1 kelvin^-1 and. B = 2 X 10^-2 calory kg^-1. If the final temperature of the vessel is 27 ° C, what will be the mass of the vessel? (latent heat of fusion of water = 8x10^4 calories kg^-1, specific heat of water = 10^3 calories kg^-1.)
Answer» An ice cube of mass 1 kg at 0 ° C is kept in a deffered container at 227 ° C. The specific heat-proportional relationship of the vessel varies with the temperature of s = A + BT, where A = 100 calories kg^-1 kelvin^-1 and. B = 2 X 10^-2 calory kg^-1. If the final temperature of the vessel is 27 ° C, what will be the mass of the vessel? (latent heat of fusion of water = 8x10^4 calories kg^-1, specific heat of water = 10^3 calories kg^-1.)