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An ideal gas has a volume of 3 V at 2 atmosphere pressure. Keeping the temperature constant. Its pressure is doubled. The volume of the gas will be |
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Answer» Solution :Given: Initial VOLUME `V_(1) = 3V` Initial pressure `P_(1) = 2` atmosphere Final pressure `P_(2) = 2P_(1) = 2 xx 2 = 4` atmosphere According to the Boyle's law we have `P_(1)V_(1) = P_(2)V_(2)` (where `V_(2)` is the final volume of gas) `or 2 xx 3V = 4xxV_(2)` or `V_(2) = 1.5V`. |
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