An ideal gas is initially at temperature T and volume V. Its volume increases by DV due to an increase in Temperature.dT, while pressure remains constant Here gamma=1/V=(dV)/(dT) What will be the nature of the graph between gamma and l?

An ideal gas is initially at temperature T and volume V. Its volume in

1.	An ideal gas is initially at temperature T and volume V. Its volume increases by DV due to an increase in Temperature.dT, while pressure remains constant Here gamma=1/V=(dV)/(dT) What will be the nature of the graph between gamma and l?
Answer» <html><body><p></p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> an ideal gas <br/> `pV=RT or ,<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=(RT)/p` <br/> When pressure remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>, we have <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(dT)=R/P`<br/> `thereforegamma=1/V(dV)/(dT)=1/VR/P=R/(RT)=1/T`<br/>i.e., `gamma T=1`=constant <br/> So the graph `gamma-T` will be a rectangular <a href="https://interviewquestions.tuteehub.com/tag/hyperbola-1034512" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERBOLA">HYPERBOLA</a> [Fig.6.20] <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U07_C06_E01_023_S01.png" width="80%"/></body></html>