An ideal gas undergoes a thermodynamic process as shown in Fig. The process consists of two isobaric and two isothermal steps. Show that the network done during the whole process is W _((Net)) = P _(1) (V _(2) - V _(1)) log _(e)""(P_(2))/( P _(1))

An ideal gas undergoes a thermodynamic process as shown in Fig. The pr

1.	An ideal gas undergoes a thermodynamic process as shown in Fig. The process consists of two isobaric and two isothermal steps. Show that the network done during the whole process is W _((Net)) = P _(1) (V _(2) - V _(1)) log _(e)""(P_(2))/( P _(1))
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> _(nct) =P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> _(B) -V _(A)) + P _(1) P_(2)<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> _(e) ( V _(2) // V _(B)) + P _(1) (V _(1) - V _(2)) + P _(1) V _(1) log (V _(A) //V_(1)) , P _(2) V _(B) = P _(1) V _(2), P _(2) V _(A) = P _(1) V _(1) W _(net) = P _(2) V _(B) - P _(2) V _(A) + P _(1) V _(2) log _(e) (P _(2) // P _(1)) + P _(1) V _(1) - P _(1) V _(2) - P _(1) V _(1) log ( P _(1) // P _(1)) = P _(1) (V _(2) - V _(1)) log _(e) ( P _(2) // P _(1))`</body></html>