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An infinite line charge produces a field of `9xx10^(-4)N" "C^(-1)` at a distance of 2 cm. calculate the linear charge density.A. `10^(-3)Cm^(2)`B. `10^(-4)Cm^(2)`C. `10^(-5)Cm^(2)`D. `10^(-7)Cm^(2)` |
Answer» Correct Answer - D Let `lambda` be the linear charge density. Electric field due to infinite line charge, `E=(lambda)/(2pi epsilon_(0)r)`. Dividing and multiplying by 2 to get `(1)/(4pi epsilon_(0))`, because we have the value of `(1)/(4pi epsilon)` `rArr" "E=(2)/(2)xx(lambda)/(2pi epsilon_(0)r)=(2lambda)/(4pi epsilon_(0)r)` Putting the values, we get `9xx10^(4)=(2xx9xx10^(9)xxlambda)/(2xx10^(-2))` `therefore" Linear charge density, "lambda=(9xx10^(4)xx2xx10^(-2))/(2xx9xx10^(9))` `=10^(-7)Cm^(-1)` Thus, the linear charge density is `10^(-7)Cm^(-1).` |
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