1.

An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 20^(@) C. The temperature at which (both for ball and plate)the ball just pass through the hole is(alpha_("iron")= 12 xx 10^(-6)//1^(@)C, alpha_("brass") = 18 xx 10^(-6) //1^(@) C)

Answer»

`68^(@) C`
`48^(@) C`
`28^(@) C`
`40^(@) C`

ANSWER :B


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