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An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 20^(@) C. The temperature at which (both for ball and plate)the ball just pass through the hole is(alpha_("iron")= 12 xx 10^(-6)//1^(@)C, alpha_("brass") = 18 xx 10^(-6) //1^(@) C) |
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Answer» `68^(@) C` |
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