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An NFA is nothing more than an ε-NFA with no ε transitions.(a) True(b) FalseThis question was addressed to me by my school teacher while I was bunking the class.My query is from The NFA with epsilon-moves to the DFA-2 topic in chapter Finite Automata and Regular Expression of Compiler

Answer»

The CORRECT answer is (a) True

Easiest EXPLANATION: An NFA is NOTHING more than an ε-NFA with no ε TRANSITIONS. Thus • δ (q, ε) for all STATES q = ∅.



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