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An organic compound has C and H percentage in the ratio 6:1 and C and O percentage in the 3:4. The compound isA. `HCHO`B. `CH_(3)OH`C. `CH_(3)CH_(2)OH`D. `(COOH)_(2)`

Answer» Correct Answer - A
% ratio of `C:H` is `6:1` and % ratio of `C:O` is `3:4`. So, % ratio of `C:H:O` is `6:1:8`. Therefore % of C comes to be `3.33%` of H is 6.66 and % of O is 3.33. Simplest ratio of `C:H:O` is `1:2:1`, i.e, `CH_(2)O`.


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