InterviewSolution
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an organic compound was found to contain the following constituents:C=33%,H=4.7%,N=130%,Cl=33.4% . Determine the Empirical formula of the compound. Hint: Calculate the percentage of oxygen since the sum of percentages of elements is not 100. The percentage of oxygen=15.7% . |
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Answer» Answer =C3H5N9ClOExplanation: HERE'S YOUR ANSWERStep -1 .. Percentage of oxygen=100--(33+4.7+13.2+33.4) = 100--84.3 = 15.7 Step -2 .. Emperical FORMULA of the organic compound.Element Percentage AM GAM Atomic RATIO SimpleratioC 33.0 12 33.0÷12 2.75÷0.94 3 =2.75 =2.93H 4.7 1 4.7÷1 4.70÷0.94 5 =4.70 =5.0N 130 14 130÷14 9.28÷0.94 9 =9.28 =9.87Cl 33.4 35.5 33.4÷35.5 0.94÷0.94 1 =0.94 =1O 15.7 16 15.7÷16 0.98÷0.94 1 =0.98 =1.04EMPERICAL FORMULA=C3H5N9ClOHOPE YOU LIKED THE ANSWERPLZ MARK ME AS BRAINLIST................ |
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