An oxide of metal `("at. wt. "= 112)` contain `12.5% O_(2)` by weight. The oxide was converted into chloride by treatment with `HCl` and electrolysed. Find the valency of metal.

An oxide of metal `("at. wt. "= 112)` contain `12.5% O_(2)` by weight.

1.	An oxide of metal `("at. wt. "= 112)` contain `12.5% O_(2)` by weight. The oxide was converted into chloride by treatment with `HCl` and electrolysed. Find the valency of metal.
Answer» Correct Answer - 2 Eq. of `O_(2) =` Eq. of metal `(12.5)/(8) = (87.5)/(E)` `:. E_("Metal") = (87.5 xx 8)/(12.5) = 56` Now valency of metal `= ("At. wt.")/("E. wt.") = (112)/(56) = 2`

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An oxide of metal `("at. wt. "= 112)` contain `12.5% O_(2)` by weight. The oxide was converted into chloride by treatment with `HCl` and electrolysed. Find the valency of metal.

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