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An unknown planet orbits the sun with distance twice the semi major axis distance of the Earth's orbit. It the Earths time period is T_(1) , what is the time period of this period is planet? |
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Answer» Solution :By Kepler.s 3rd LAW`T^(2)prop a^(3)` TIME periodof unknownplanet = `T_(2)` Time PERIOD of EARTH =`T_(1)` Distance of unknown PLANET from the Sun= `a_(2)` `(T_(1)^(2))/(T_(2)^(2)) = (a_(1)^(2))/(a_(2)^(3))` `T_(2) = ((a_(2))/(a_(1)))^(3/2)T_(1)""a_(2)=2a` `T_(2) = ((2a_(1))/(a_(1)))^(3/2)T_(1) rArrT_(2) =2sqrt(2)T_(1)` |
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