1.

Analysis shows that a metal oxide has the empirical formula M 0.98° 1.00. Calculate the percentage of M2+ and M3+ ions in the crystal.

Answer»

Let the M2+ ion in the crystal be x and M3+ =0.98 ‐ x 

Since total change on the compound must be zero 

2x + 3(0.098 ‐ x) ‐ z = 0 

X = 0.88 

%of M2+ 0.88/0.96*100 = 91.67 

% of M3+ = 100 ‐ 91.91.67 = 8.33



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