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As shown in figure waves with identical wavelengths and amplitudes and which are intially in phase travel through difference media. Ray 1 travels through air and Ray 2 through a transparent medium for equal length L, in four different situations. Rays reach a common point on the screen. The number of wavelengths in length L is `N_(2)` for Ray 2 and `N_(1)` for Ray 1. In the following table, values of `N_(1)` and `N_(2)` are given for all four situations. The order or the situations according to the intensity of the light at the common point in descending order is Situations 1 2 3 4 `N_(1)` 2.75 1.80 3.00 3.25 `N_(2)` 2.75 2.80 3.25 4.00 A. `I_(3)=I_(4)gtI_(2)gtI_(1)`B. `I_(1)gtI_(3)=I_(4)gtI_(2)`C. `I_(1)gtI_(2)gtI_(3)gtI_(4)`D. `I_(2)gtI_(3)=I_(4)gtI_(1)` |
Answer» Correct Answer - D Path difference `Deltax_(1)=(lamda)/(2),Deltax_(2)=lamda,Deltax_(3)=(lamda)/(4),Deltax_(4)=(3lamda)/(4)` Therefore `I_(2)gtI_(3)=I_(4)I_(1)` |
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