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ASIS2usonan 75ITE be an event, then P(E) + P(not E) =(a) o(b)-1E be an event, then PCE) + P(not E) -(c) 1(d) none of these​

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Answer:

given E is a certain EVENT and P(E) denotes the PROBABILITY of the event E.

We know that, "An event is SAID to be a Certain Event if there is an absolute surety on the CHANCE of its occurrence." The probability of certain event is said to be 1.

Therefore, P(E)=1.



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