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At a metro station, a girl walks up a stationary escalator in time. t _(1),If she remains stationary on the escalator, then the escalator take her up in time t_(2). The time taken by her to walk up on the moving escalator will be |
Answer» <html><body><p>`(t_(1) +t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) //2`<br/>`t _(1) t _(2) // (t - t _(1))`<br/>`t _(1) t _(2) //(t_(2) + t _(1))`<br/>`t _(1) - t _(2)` </p>Solution :Net velocity with respectto the Earth that will be equal to velocity of the girl plus velocity of esaclator. <br/> Let displacemtn is L, then <br/> velocity of girl `v _(g) = (L)/(t _(1)) ` <br/> velocity of escaltoor `v _(e) = (L)/(t _(2))` <br/> Net velocity of the girl, `v =v _(g) + v _(e) = (L)/(t_(1)) + (L)/(t_(2)) ...(i)` <br/> If t is total time taken in covering distance L, then `v = L/t` <br/> Using in (i) `L/t = (L)/(t _(1)) + (L)/(t _(2)) <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> t = (t_(1) t_(2))/(t _(1) + t _(2))`</body></html> | |