At what concetration of `Ag^(2+)` ions, will the electrode have a pote

1.	At what concetration of `Ag^(2+)` ions, will the electrode have a potential of 0.0 V?
Answer» Correct Answer - `2.9xx10^(-14) M` `Ag^(+)+e^(-) to Ag`. `(E_(Ag)^(+))/(Ag) to (E_(Ag^(+))^(@))/(Ag)-(0.0591)/(n)"log"(1)/([Ag^(+)])` `0=0.80-(0.0591)/(1)"log"(1)/([Ag^(+)])=0.80+0.0591 " log "[Ag^(+)]` `[Ag^(+)]=((-)0.80)/(0.0591)=-13.5364=overset(-" ")14.4636`. `[Ag^(+)]="Antilog "log[overset(-" ")14.4636]=2.9xx10^(-14)" M "`.

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At what concetration of `Ag^(2+)` ions, will the electrode have a potential of 0.0 V?

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