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`AX,AY,BX`, and `BY` have rock salt type structure with following internuclear distances: `|{:("Salt","Anion-anion","Cation-anion"),(,"distance in"Å,"distance in"Å),(AX,2.40,1.70),(AY,1.63,1.15),(BX,2.66,1.88),(By,2.09,1.48):}|` Ionic radii of `A^(o+)` and `B^(o+)`, respectively, areA. `0.35` and `0.68 Å`B. `0.68` and `0.35 Å`C. `1.20` and `0.80 Å`D. `0.80` and `1.20 Å` |
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Answer» Correct Answer - A `Y^(ɵ)` is small than `X^(ɵ)`. The difference in internucler distanc between `AX` and `BX` indicates that the cation must not be touching apl the anions in `AX` (smaller cation, larger anion) [see `Q.10`, Fig.(a)]. There must ve anion-anion contact is this compound. `:.` Anion-anion ditance = `2r_(ɵ)` The remaining radius ratio is represented in (see `Q.9` Figure]. b. Radius of `X^(ɵ)(r_(ɵ)) = (2.40)/(2) = 1.20Å` Radius of `B^(o+)(r_(o+)) = (1.88 - 1.20)Å = 0.68Å` c. Similarly, radius of `Y^(ɵ)(r_(ɵ)) = (1.48 - 0.68) = 0.80 Å` Radius of `A^(o+)(r_(o+)) = (1.15 - 0.80)Å = 0.35 Å` Radius of `A^(o+)` and `B^(o+)`, respectively, are `= 0.35` and `0.68Å` |
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