(Ăź) The amount of air present in a cylinder when a vacuum pump remo

1.	(Ăź) The amount of air present in a cylinder when a vacuum pump removes - of the4air remaining in the cylinder at a time.
Answer» Solution:Let us assume, initial quantity of air = 1 Therefore, quantity removed in first step = ¼ Remaining quantity after first step =1−14=34=1-14=34 Quantity removed in second step =34×14=316=34×14=316 Remaining quantity after second step =34−316=12−316=916=34-316=12-316=916 Here each subsequent term is not obtained by adding a fixed number to the previous term. Hence, it is not an AP.

(Ăź) The amount of air present in a cylinder when a vacuum pump removes - of the4air remaining in the cylinder at a time.

Answer»

Solution:Let us assume, initial quantity of air = 1

Therefore, quantity removed in first step = ¼

Remaining quantity after first step

=1−14=34=1-14=34

Quantity removed in second step

=34×14=316=34×14=316

Remaining quantity after second step

=34−316=12−316=916=34-316=12-316=916

Here each subsequent term is not obtained by adding a fixed number to the previous term.

Hence, it is not an AP.