Step 1:

Rewrite the given equation as it is

H₂SO_4(aq) + NaO_(aq) → Na₂SO_4(aq) + H₂O_(I)

Step 2:

write the number of atoms of each element in the unbalanced equation on both sides of the equation.

The number of oxygen atoms involved in different compounds on both sides (reactants and products) are equal. Therefore, balance the number of atoms of the second element, sodium.

Step 3:

To balance the number of sodium atoms:

To equalise the number of sodium atoms, we use 2 as the factor of NaOH in the reactants. Now, the partly balanced equation becomes as follows

H₂SO₄ + 2NaOH → Na₂SO₄ + H₂O

Step 4:

Now, balance the number of hydrogen atoms:

To equalise the number of hydrogen atoms, we use 2 as the factor or H₂O in the products. The equation then becomes

H₂SO₄ + 2NaOH → Na₂SO₄ + H₂O

Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is

H₂SO₄ + 2NaOH → Na₂SO₄ + H₂O

Now indicate the physical states of the reactants and the products.

H₂SO_4(aq) + 2NaOH_(aq) → Na₂SO_4(aq) + 2H₂O_(I)