Based on the following reaction, `XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(aq) rarr XeO_(3)(aq)+F_(2)(g)+3H_(2)O(l)` (`Delta (G)^(@)lto`) It can be concluded thatA. oxidising power of `F^(-)` is grater than that of `XeO_(6)^(4-)`B. it is not a redox reactionC. it is a disproportionation reactionD. oxidising power of `XeO_(6)^(4-)` is greater than that of `F^(-)`

Based on the following reaction, `XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(a

1.	Based on the following reaction, `XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(aq) rarr XeO_(3)(aq)+F_(2)(g)+3H_(2)O(l)` (`Delta (G)^(@)lto`) It can be concluded thatA. oxidising power of `F^(-)` is grater than that of `XeO_(6)^(4-)`B. it is not a redox reactionC. it is a disproportionation reactionD. oxidising power of `XeO_(6)^(4-)` is greater than that of `F^(-)`
Answer» Correct Answer - D `underset((+8))underset(uarr)(XeO_(6)^(4-))+underset((-1))underset(uarr)(F^(-) ) rarr underset((+6))underset(uarr) (XeO_(3))+underset((0))underset(uarr) (F_(2))` Since, `DeltaG^(@)lt0`, hence it is spontaneous in forward direction. Oxidation number of `Xe` decreases, hence, it is an oxidising agent, and oxidation number of `F` increases, hence it is a reducing agent.

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