InterviewSolution
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InterviewSolution
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Block `A` is hanging from vertical spring of spring constant `K` and is rest. Block `B` strikes block `A` with velocity `v` and sticks to it. Then the value of `v` for which the spring just attains natural length is A. `sqrt((60mg^(2))/(k)`B. `sqrt((6mg^(2))/(k)`C. `sqrt((10mg^(2))/(k)`D. `sqrt((mg^(2))/(k)` |
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Answer» Correct Answer - B `x_(0) = (mg)/(k)`, after the collision speed of combined mass is `(V)/(2)`. `(1)/(2) xx 2m((v^(2))/(2))+(1)/(2)k((mg)/(k))^(2) = 2 mg((mg)/(k))` so, `V = sqrt((6mg^(2))/(k))` |
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