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By using the method of completing the square, show that the equation `4x^(2)+3x+5=0` has no real roots. |
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Answer» We have `4x^(2)+3x+5=0` `implies" "4x^(2)+3x=-5` `implies" "(2x)^(2)+2xx2x xx(3)/(4)+((3)/(4))^(2)=-5+((3)/(4))^(2)` `" "["adding "((3)/(4))^(2)" on both sides"]` `implies" "(2x+(3)/(4))^(2)=(-5+(9)/(16))=((-80+9))/(16)=(-71)/(16)lt0.` But, `(2x+(3)/(4))^(2)` conot be negative for any real value of x. So, there is no real value of x satisfying the given equation. Hence, the given equation has no real roots. |
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