.C+O2 → CO2, Consider 3g of C reacts with 16g of O2 then find Limiti

1.	.C+O2 → CO2, Consider 3g of C reacts with 16g of O2 then find Limiting reagent
Answer» C(s) + O 2 →CO 2 (G) No. of MOLES of carbon = 12 36 =3 moles No. of moles of oxygen = 32 32 =1 moles So, 2 moles of carbon is left and oxygen will be completed. So, O 2 is limiting reagent.Explanation:

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