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Caculate the electric field due to a dipole on its axial line and equatorial line ​

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/electric-967871" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRIC">ELECTRIC</a> field due to dipole is given by, </p><p>but <a href="https://interviewquestions.tuteehub.com/tag/ea-444752" style="font-weight:bold;" target="_blank" title="Click to know more about EA">EA</a>=1/4πEo q/(r+h) <a href="https://interviewquestions.tuteehub.com/tag/2and-300622" style="font-weight:bold;" target="_blank" title="Click to know more about 2AND">2AND</a> Eb=1/4πEo q/(r-h) 2</p><p>as Eb&gt;Ea and act in opposite direction so </p><p>E=1/4πEo q/(r-h) 2 - 1/4πEo q/(r+h) 2=1/4πEo q(4rh)/(r2-h2) 2</p><p>but q×2h=p,the dipole moment</p><p>E =1/4πEo 2pr/(r2-a2)2 (along px) </p><p>for short dipole, neglecting <a href="https://interviewquestions.tuteehub.com/tag/a2as-1958449" style="font-weight:bold;" target="_blank" title="Click to know more about A2AS">A2AS</a> compared to r2, E=2p/4πEor3 I. e. E=p/2πEor3</p></body></html>


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