1.

Calcium carbonate is decomposed on heating in the following reaction CaCO3 → CaO + CO2 1. How many moles of Calcium carbonate is involved in this reaction? 2. Calculate the gram molecular mass of calcium carbonate involved in this reaction.3. How many moles of CO2 are there in this equation?

Answer»

CaCO3 → CaO + CO2 

1. 1 mole of CaCO3 is involved in this reaction. 

2. Gram molecular mass of calcium carbonate CaCO3 = (40 + 12 + 3 × 16) = 52 + 48 = 100 g 

3. 1 mole of CO2 is in this equation.



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