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Calculate emf of the following cell reaction at 2968 K : `Ni(s)//Ni^(2+)(0.01 M) || Cu^(2+)(0.1 M)//Cu(s)` [Given `E_(Ni^(2+)//Ni)^(@)=-0.25" V ",E_(Cu^(2+)//Cu)^(@)=+0.34 " V "`] Write the overall cell reaction. |
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Answer» Correct Answer - 0.6195V According toNernst Equation : `E=E^(@)-(0.0591)/(n)"log"([Ni^(2+)])/([Cu^(2+)])=0.59-(0.0591)/(2)"log"([0.01])/([0.1])` `E=0.59-0.0295(-1)=0.6195" V "` |
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