Calculate equilibrium constant for the reaction at `25^(@)C` `Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s)` `E^(@)` value of the cell is 0.46`" V "`.

Calculate equilibrium constant for the reaction at `25^(@)C` `Cu(s)+2A

1.	Calculate equilibrium constant for the reaction at `25^(@)C` `Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s)` `E^(@)` value of the cell is 0.46`" V "`.
Answer» Correct Answer - `3.67xx10^(15)` `logK_(C)=nE_(cell)^(@)//0.0591,E_(cell)^(@)=0.46" V ",n=2` `:." "logK_(C)=(2xx0.46)/(0.0591)=15.567,k_(C)=3.67xx10^(15)`.

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