1.

Calculate heat required to convert 3 kg of water at 0ºC to steam at 100ºC. Given specific heat capacity of H2O = 4186 J kg–1k–1 and latent heat of steam = 2.256 × 106 J/kg.

Answer»

Heat required to convert H2O at 0º to H2O at 100º = m1c1t

= 30 × 4186 × 100 = 1255800 J 

Heat required to convert H2O at 100ºC to steam at 100ºC is = mL 

= 3 × 2.256 × 106 

= 6768000 J 

Total heat = 8023800 J



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