Calculate `K_(c)` for the reaction at 298 K `Zn_((s))+Cu_((aq))^(+2)hArrZn _((aq))^(2+)+Cu_((s))` `E _(Zn^(2+)//Zn)^(0)=-0.76V, E_(Cu^(2+)//Cu)^(0) =+0.34V.`

Calculate `K_(c)` for the reaction at 298 K `Zn_((s))+Cu_((aq))^(+2)hA

1.	Calculate `K_(c)` for the reaction at 298 K `Zn_((s))+Cu_((aq))^(+2)hArrZn _((aq))^(2+)+Cu_((s))` `E _(Zn^(2+)//Zn)^(0)=-0.76V, E_(Cu^(2+)//Cu)^(0) =+0.34V.`
Answer» Given `Zn_((s))+Cu_((aq))^(+2)hArrZn _((aq))^(2+)+Cu_((s))` ` E^(0)of Zn ^(+2)//Zn=-0.76V` `E^(0)of Cu^(+2) //Cu =-0.34V` `E^(0)of cell =E_(RHS)-E_(LHS ) =0.34=(-0.76)=1.1V` `DeltaG^(0) =-RT//ln K_(c)=-2.303RT log K_(c)` `-212300=-2.303xx8.314xx298xxlog K _(c)` `log K_(c) =(212300)/(2.303xx8.314xx298)=37.207` `K_(c) =1.6xx10^(37)`

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Calculate `K_(c)` for the reaction at 298 K `Zn_((s))+Cu_((aq))^(+2)hArrZn _((aq))^(2+)+Cu_((s))` `E _(Zn^(2+)//Zn)^(0)=-0.76V, E_(Cu^(2+)//Cu)^(0) =+0.34V.`

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