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Calculate tbe molar mass of the following compounds.(a) Urea (NH2CONH2) (b) Ethanol(C5H5OH); (c) Boric acid (H3BO3)[Atomic mass of N – 14, H – 1, C – 12, B – 11, O – 16] |
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Answer» (a) Urea (NH2CONH2) = 2(14) + 4(1) + 1(16) + 1(12) = 28 + 4 + 16 + 12 = 60 g (b) Ethanol(C2H5OH) = 2(12) + 6(1) + 1(16) = 24 + 6 + 16 = 46 g (c) Boric acid (H2BO3) = 3(1) + 1(11) + 3(16) = 3 + 11 + 48 = 62 g |
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