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Calculate the approximate number of unit cells present in 1 g of gold. Given that gold cyrstallises in a face centred cubic lathce (Given atomic mass of gold = 197 u). |
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Answer» Mole of Au=`1/197` Number of atoms of Au=`(6.022xx10^23)/197` Total number of unit cells =`(6.022xx10^23)/(197xx4)=7.64xx10^20` |
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